1. Tardigrade
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  3. Chemistry
  4. Following solutions were prepared by mixing different volumes of NaOH and HCl of different concentrations 1. 60 mL of (M/10 )HCl+40 mL of (M/10 )NaOH 2. 55 mL of (M/10 )HCl+45 mL of (M/10 )NaOH 3. 75 mL of (M/5 )HCl+25 mL of (M/5 )NaOH 4. 100 mL of (M/10 )HCl+100 mL of (M/10 )NaOH pH of which one of them will be equal to 1?

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Q. Following solutions were prepared by mixing different volumes of NaOH and HCl of different concentrations

$1.$ $60$ $mL \, of \, \frac{M}{10 \, }HCl+40$ $mL \, of \, \frac{M}{10 \, }NaOH$

$2.$ $55$ $mL \, of \, \frac{M}{10 \, }HCl+45$ $mL \, of \, \frac{M}{10 \, }NaOH$

$3.$ $75 \, mL \, of \, \frac{M}{5 \, \, }HCl+25$ $mL \, of \, \frac{M}{5 \, }NaOH$

$4.$ $100$ $mL \, of \, \frac{M}{10 \, \, }HCl+100 \, mL \, of \, \frac{M}{10 \, }NaOH$

pH of which one of them will be equal to 1?

NTA AbhyasNTA Abhyas 2020Some Basic Concepts of Chemistry

Solution:

Meq of HCl $=75\times \frac{1}{5}\times 1=15$

Meq of NaOH $=25\times \frac{1}{5}\times 1=5$

Meq of HCl in resulting solution = 10

Normality of $\left[\right.H^{+}\left]\right.$ in resulting mixture $=\frac{10}{100}=\frac{1}{10}$

$pH=-log\left[\right.H^{+}\left]\right.=-log\left[\frac{1}{10}\right]=1.0$