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Q. Following figures show different combinations of identical bulb(s) connected to identical battery(ies). Which option is correct regarding the total power dissipated in the circuit?
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KVPYKVPY 2012

Solution:

Power consumed in each case is
(P) $\quad P=\frac{V^{2}}{3 R}$
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(Q)$P=\frac{V^{2}}{R / 3}=\frac{3 V^{2}}{R}$
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(R)$P=\frac{V^{2}}{R}$
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(S)$P=\frac{(2 V)^{2}}{R}=\frac{4 V^{2}}{R}$
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So, order of increasing power consumption is
$P >R >Q >S$.