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Q.
Following diagram performs the logic function of
BHUBHU 2007Semiconductor Electronics: Materials Devices and Simple Circuits
Solution:
For our convenience, the output of first NAND gate is chosen as X as shown,
Output is first NAND gate.
$X=\overline{A \cdot B}$
Using De-Morgan's theorem,
$\overline{A . B}=\bar{A}+\bar{B} $
So $X=\bar{A}+\bar{B}$
Now, output of $2 \,nd$ NAND gate,
$Y=\bar{X}=\overline{\bar{A}+\bar{B}} $
again$ \overline{\bar{A}+\bar{B}}=\overline{\bar{A}} \cdot \overline{\bar{B}}=A \cdot B$ $(\because \overline{\bar{A}}=A)$
Hence, $ Y=A \cdot B$
This is the logic function of AND aate.