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Q. Following circuit will act as:Physics Question Image

JIPMERJIPMER 2019

Solution:

output of gate 1 is, $y_1$ = $\bar{A}$

output of gate 2 is, $y_1$ = $\bar{B}$
Then the output of gate 3 is$\Rightarrow y_{3}=\overline{\bar{A}\bar{B}}$
= A + B
So the output of gate 4 is,
$y_{4}=\overline{\left(A+B\right).\left(A+B\right)} \Rightarrow \overline{A+B}$
So the circuit acts as a NOR Gate.

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