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  4. Focii of ((x-1)2/25)+((y-1)2/9)=1 are ....

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Q. Focii of $\frac{(x-1)^2}{25}+\frac{(y-1)^2}{9}=1$ are ....

KCETKCET 2022

Solution:

given $, a^{2}=25, b^{2}=9, h=1=k$
$a e=\sqrt{a^{2}-b^{2}}=\sqrt{16}=4$
focii are $(h \pm ae,k)=(1 \pm 4,1)$
$\therefore(5,1)\, \&\,(-3,1)$