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Q.
Flow rate of blood through a capillary of cross-sectional area of $0.25 \, m^{2}$ is $100 \, c m^{3} / s$ $$ . The velocity of flow of blood is
NTA AbhyasNTA Abhyas 2020
Solution:
For the blood flow in capillary, Volumetric flow rate = velocity × area of cross-section
$ \, v=\frac{Q}{A}=\frac{100 \times 1 0^{- 6}}{0.25}$
Q=Av
$v=400 \, \times 10^{- 3} \, m m / s=0.4 \, m m / s$