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Q. Five resistances of resistance $ R\,\Omega $ are there, $3$ are connected in parallel and are joined to them in series. Find resultant resistance:

Rajasthan PMTRajasthan PMT 2006Current Electricity

Solution:

$ \frac{1}{R_{P}} =\frac{1}{R}+\frac{1}{R}+\frac{1}{R}=\frac{3}{R} $
$ \Rightarrow R_{P} =\frac{R}{3} \Omega$
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$ R_{5} =R+R=2 R\, \Omega $
$R_{\text {net }} =R_{P}+R_{S} $
$=2 R+\frac{R}{3}=\frac{7 R}{3} \,\Omega$