Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
Five moles of an ideal gas expands reversibly from a volume of 8 dm3 to 80 dm3 at a temperature of 27°C. Calculate the change in entropy.
Question Error Report
Question is incomplete/wrong
Question not belongs to this Chapter
Answer is wrong
Solution is wrong
Answer & Solution is not matching
Spelling mistake
Image missing
Website not working properly
Other (not listed above)
Error description
Thank you for reporting, we will resolve it shortly
Back to Question
Thank you for reporting, we will resolve it shortly
Q. Five moles of an ideal gas expands reversibly from a volume of $8\, dm^3$ to $80\, dm^3$ at a temperature of $27^{\circ}C$. Calculate the change in entropy.
Thermodynamics
A
$70.26\, JK^{-1}$
B
$82.55\, JK^{-1}$
C
$95.73\, JK^{-1}$
D
$107.11\, JK^{-1}$
Solution:
Entropy change $\left(\Delta S\right)=2.303 nRT log \frac{V_{2}}{V_{1}}$
$=2.303\times5\times8.314\times log \frac{80}{8}=95.73 JK^{-1} $