Thank you for reporting, we will resolve it shortly
Q.
Five digit number divisible by 3 is formed using 0, 1, 2, 3, 4,5, 6 and 7 without repetition. Total number of such numbers are
Permutations and Combinations
Solution:
$0,1,2,3,4,6$ and 7
number should be divisible by 3
If No. to be divisible by 3 the sum of digits should be divisible by 3
$\therefore$ cases will be
$1,3,4,6,7=21$ divisible so, $5 !=120$
$0,1,4,6,7=18$ divisible so, $4 \cdot 4 !=96$
$0,2,3,6,7=18$ divisible $s 0,4 \cdot 4 !=96$
$0,1,3,4,7=15$ divisible so, $4 \cdot 4 !=96$
$0,2,3,4,6=15$ divisible so,4 $\cdot 4 !=96$
$0,1,2,3,6=12$ divisible so,4 $4 !=96$
Therefore total $=600$. Answer