1. Tardigrade
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  3. Chemistry
  4. First and second ionization energies of magnesium are 7.646 and 15.035 eV respectively. The amount of energy in kJ / mol needed to convert all the atoms of Magnesium into Mg 2+ ions present in 12 mg of magnesium vapours is: (Report your answer by multiplying with 10 and round it upto nearest integer) [Given: 1 eV =96.5 kJ mol -1 ]

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Q. First and second ionization energies of magnesium are $7.646$ and $15.035\, eV$ respectively. The amount of energy in $kJ / mol$ needed to convert all the atoms of Magnesium into $Mg ^{2+}$ ions present in $12 \,mg$ of magnesium vapours is: (Report your answer by multiplying with $10$ and round it upto nearest integer) [Given: $1 \,eV =96.5\, kJ\, mol ^{-1}$ ]

NTA AbhyasNTA Abhyas 2020Classification of Elements and Periodicity in Properties

Solution:

$\frac{12\, mg }{24 \,g }=0.5 \times 10^{-3}$ moles
Energy per atom $=7.646+15.035=22.68 \,eV$
$22.68 \times 96.48=21.88 \times 10^{2} kJ / mol$
$E$ (needed) $21.88 \times 10^{2} \times 0.5 \times 10^{-3}$
$10.94 \times 10^{-1}=1.094\, kJ / mol$