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Mathematics
Find total number of divisors of 480 , that are of the form 4 n+2, n ≥ 0.
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Q. Find total number of divisors of $480$ , that are of the form $4 n+2, n \geq 0$.
Permutations and Combinations
A
B
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D
Solution:
$480=2^{5} \times 3^{1} \times 5^{1}$
$(4 n +2)$ divisor $=$ Groups taking exactly one $2$
$=1 \times 2 \times 2$
$=4$