Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. Find the velocity of centre of mass of the system shown in the figure?Physics Question Image

System of Particles and Rotational Motion

Solution:

Here $m_1=1 \, kg, v_1=2 \hat {i},$
$m_2=2\,kg,v_2=2 \, \cos 30^{\circ} \hat {i}-2\sin \, 30^{\circ} \hat {j}$
$v_{CM}= \frac {m_1v_1+m_2v_2}{m_1+m_2} $
$= \frac {1 \times 2i+2(2\cos 30^{\circ} \hat {i}-2\sin 30^{\circ} \hat {i})}{1+2}$
$ =\frac {2 \hat {i}+2 \sqrt 3 \hat {i}-2 \hat {j}}{3} $
$=\left (\frac {2+2 \sqrt 3}{3}\right )\hat {i}- \frac {2}{3} \hat {j} $