Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. Find the value of $ \sin \,(2\,{{\tan }^{-1}}x),\,|x|\le 1 $

J & K CETJ & K CET 2014Inverse Trigonometric Functions

Solution:

$ \sin (2{{\tan }^{-1}}x)=\sin \left( {{\sin }^{-1}}\frac{2x}{1+{{x}^{2}}} \right) $
$ =\frac{2x}{1+{{x}^{2}}},-1\le x\le 1 $