Q. Find the value of $\sqrt{18}+\sqrt{12}$, if $\sqrt{2}=1.414$ and $\sqrt{3}$ $=1.732$ The following steps are involved in solving the above problem. Arrange them in sequential order. (A) $4.242+3.464=7.706$ (B) $3 \sqrt{2}+2 \sqrt{3}$ (C) $\sqrt{18}+\sqrt{12}=\sqrt{3^2 \times 2}+\sqrt{2^2 \times 3}$ (D) $3(1.414)+2(1.732)$
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