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Q. Find the sum of the abscissas of the points lying on the line $x-y=3$, which lies at a unit distance from $4 x-3 y=12$.

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Solution:

Let the point is $(a, a-3)$
$\Rightarrow\left|\frac{4 a-3(a-3)-12}{5}\right|=1$
$\Rightarrow |a-3|=5$
$\Rightarrow a=8,-2$
$\therefore$ sum $=6$