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Q. Find the resonance frequency in the given circuit:Physics Question Image

JIPMERJIPMER 2019Alternating Current

Solution:

After simplifying the circuit, we get,
$L_{eq} = \frac{L.L}{L+L}=\frac{L}{2}$
$C_{eq} = C + C = 2C$
Resonance frequency
$\omega = \frac{1}{\sqrt{L_{eq} C_{eq}}}$
$\omega = \frac{1}{\sqrt{\frac{L}{2}2C}}=\frac{1}{\sqrt{LC}}$

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