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Q.
Find the radius of the circle in which a central angle of $60^{\circ}$ intercepts an arc of length $37.4 \,cm$ (use $\pi=\frac{22}{7}$).
Trigonometric Functions
Solution:
Here $l=37.4\,cm$ and $\theta=60^{\circ}=\frac{60\pi}{180}$ radian $=\frac{\pi}{3}$
Hence, by $r=\frac{l}{\theta}$, we have
$r=\frac{37.4 \times 3}{\pi}=\frac{37.4 \times 3 \times 7}{22}$
$=35.7\,cm$