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Q. Find the principal value $cos^{-1} \left(\frac{1}{2}\right)$

Inverse Trigonometric Functions

Solution:

Let $\cos^{-1} \left(\frac{1}{2}\right) = \theta$
$\Rightarrow \,\cos\,\theta = \frac{1}{2}$
$= \cos \frac{\pi}{3}$
$\Rightarrow \, \theta = \frac{\pi }{3}\in\left[0, \,\pi\right]$
$\therefore $ Principal value of $\cos^{-1} \left(\frac{1}{2}\right)$ is $\frac{\pi }{3}$