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Q.
Find the potential difference between $a$ and $b$, as shown in the below circuit,
TS EAMCET 2019
Solution:
The circuit can be redrawn as,
$45\, V$ is drop across the branch one, so current through it,
$I_{1}=\frac{45}{R_{ eq _{1}}}=\frac{45}{\frac{15}{4}}=12\, A$
Now, above circuit can be redrawn as,
Since, in a series circuit, the current flows will be same,
hence, $V_{a b}=I_{a b} R_{e q}(a b)=12\left(\frac{15}{4}+4+10\right)$
$\Rightarrow V_{a b}=213\, V$
