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Q.
Find the molality of $H_{2}SO_{4}$ solution whose specific gravity is $1.98\, g \,ml^{-1}$ and 95% by volume $H_{2}SO_{4}$
Solutions
Solution:
$H_{2}SO_{4}$ is 95% by volume
wt. of $H_{2}SO_{4}=95\,g$
Vol of solution = 100 ml
$\therefore $ Moles of $H_{2}SO_{4}=\frac{95}{98}$, and weight of solution
$=100 \times 1.98=198\,g$
Weight of water $= 198 - 95 = 103 \,g$
Molality $=\frac{95 \times 1000}{98\times 103}=9.412$
Hence molality of $H_{2}SO_{4}$ solution is 9.412