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Q. Find the minimum value of $m$ so that the block $\left(\right.10kg\left.\right)$ do not move :-
Question

NTA AbhyasNTA Abhyas 2020

Solution:

$N=\left(\right.10+m\left.\right)g$
$f=\mu N=\frac{1}{3}\left(\right.10+m\left.\right)g$
$6g\leq \frac{1}{3}\left(\right.10+m\left.\right)g$
$8\leq m$
$m_{min}=8kg$