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  4. Find the mean number of heads in three tosses of a fair coin :

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Q. Find the mean number of heads in three tosses of a fair coin :

KCETKCET 2022Probability - Part 2

Solution:

X 0 1 2 3
$P(x)$ $\frac{1}{8}$ $\frac{3}{8}$ $\frac{3}{8}$ $\frac{1}{8}$

Mean $=\frac{3}{8}+\frac{6}{8}+\frac{3}{8}=\frac{12}{8}=\frac{3}{2}=1.5$