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Q. Find the maximum value of the sum of the A.P. $30,27,24,21, \ldots \ldots$

Sequences and Series

Solution:

Let $I _{ n }=0$
$30+(n-1)(-3)=0 $
$n-1=10 $
$n=11$
Sum is max if $n=11$
Max sum $=\frac{11}{2} [30]$
$=\frac{330}{2}=165$