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Q. Find the least number which when divided by 15,25 , and 35 respectively, leaves remainder 6,16 , and 26 .

Real Numbers

Solution:

$15-6=9$
$25-16=9 $
$35-276=9$
$\therefore$ The Required number will be LCM of (15,25,35) k-9$
image
$\therefore \operatorname{LCM}(5,25,35)=525 \text {. }$
Therefore, required number $=525 k-9$.
If $k=1$, the number will be 516 .