Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. Find the gravitational force of attraction between the ring and sphere as shown in the diagram, where the plane of the ring is perpendicular to the line joining the centres. If $\sqrt{8} R$ is the distance between the centres of a ring (of mass 'm') and a sphere (mass 'M') where both have equal radius 'R'.
image

JEE MainJEE Main 2021Gravitation

Solution:

Gravitational field of ring
$=-\frac{Gmx}{\left( R ^{2}+ x ^{2}\right)^{3 / 2}}$
Force between sphere & ring
$=\frac{{GmM}(\sqrt{8} R )}{\left( R ^{2}+8 R ^{2}\right)^{3 / 2}}$
$=\frac{{GmM}}{ R ^{2}} \times \frac{\sqrt{8}}{27}$