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  4. Find the distance between points P(2,-(π/6)) and Q(3, (π/6))

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Q. Find the distance between points $P\left(2,-\frac{\pi}{6}\right)$ and $Q\left(3, \frac{\pi}{6}\right)$

Straight Lines

Solution:

$P Q=\sqrt{r_1^2+r_2^2-2 r_1 r_2 \cos \left(\theta_1-\theta_2\right)}$
$=\sqrt{4+9-6}=\sqrt{7}$