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Q.
Find the direction cosines of the line joining $A(0,7,10)$ and $B(-1, 6,6)$.
Three Dimensional Geometry
Solution:
Direction ratios of $AB$ are $\left(-1, -0, 6-7, 6-10\right)$
or $\left(-1, -1, -4\right)$
Also, $\sqrt{\left(-1\right)^{2}+\left(-1\right)^{2}+\left(-4\right)^{2}}$
$=3\sqrt{2}$
$\therefore $ Direction cosines are $\left(-\frac{1}{3\sqrt{2}}, -\frac{1}{3\sqrt{2}}, \frac{-4}{3\sqrt{2}}\right)$
or $\left(\frac{1}{3\sqrt{2}}, \frac{1}{3\sqrt{2}}, \frac{4}{3\sqrt{2}}\right)$