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  4. Find out the rise of column of liquid with in a fine capillary tube. If density of liquid =103, angle of contact =60°, acceleration due to gravity =10 m / s 2, surface tension =70 × 10-3 N / m, radius of capillary tube =0.2 mm .

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Q. Find out the rise of column of liquid with in a fine capillary tube. If density of liquid $=10^{3}$, angle of contact $=60^{\circ}$, acceleration due to gravity $=10 m / s ^{2}$, surface tension $=70 \times 10^{-3} N / m$, radius of capillary tube $=0.2 mm .$

JIPMERJIPMER 2019

Solution:

The ascent formula for the rise of liquid in a capillary tube is,
$ h = \frac{2T\,cos\,\theta}{r\rho g}=\frac{2\times70\times10^{-3}\,cos\,60^{\circ}}{2\times10^{-4}\times10^{3}\times10}$
$= \frac{7}{2}\,$cm = 3.5 cm