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Q. Find out the percentage dissociation of an acid having conc. of $\text{10} \, \text{M}$ and dissociation constant $1.0\times 10^{- 3}$ .

NTA AbhyasNTA Abhyas 2020Equilibrium

Solution:

$\alpha =\sqrt{\frac{1 0^{- 3}}{10}}=10^{- 2}$

$\%\alpha =10^{- 2}\times 100=1\%$