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Q.
Find out the number o f base pairs in E. coli DNA if
its DNA is 1.36 mm long.
Molecular Basis of Inheritance
Solution:
In the given case, the number of base pairs for E. coli would be $4 \times 10^{6}$ bp. It can be calculated as
Average distance between two base pairs of DNA is $3.4 \,\mathring{A}$.
Length of $E$. coli DNA is $=1.36 \times 10^{7} \,\mathring{A}$
So, number of nucleotides $=\frac{1.36 \times 10^{7}\,\mathring{A}}{3.4 \,\mathring{A}}=0.39 \times 10^{7}$
$=3.9 \times 10^{6} \cong 4 \times 10^{6} bp$