Q. Find out the bond order in $He _{2}, He _{2}^{+}, O _{2}$ and $O _{2}^{+}$, respectively
TS EAMCET 2020
Solution:
Bond order $=\frac{\text { bonding electrons }-\text { antibonding electrons }}{2}$
Molecules
Bond order
$He _{2}$
$\frac{2-2}{2}=0$
$He _{2}$
$\frac{2-1}{2}=0.5$
$O_{2}$
$\frac{10-6}{2}=2$
$O _{2}^{+}$
$\frac{10-5}{2}=2.5$
| Molecules | Bond order |
|---|---|
| $He _{2}$ | $\frac{2-2}{2}=0$ |
| $He _{2}$ | $\frac{2-1}{2}=0.5$ |
| $O_{2}$ | $\frac{10-6}{2}=2$ |
| $O _{2}^{+}$ | $\frac{10-5}{2}=2.5$ |