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  4. Find Ecell° for the reaction: 3Zn(.s.)+2(Cr)+ 3(.aq..) arrow 3(Zn)+ 2(.aq..)+2Cr(.s.) Given: E((Zn)+ 2 / Zn)o=-0.76V;E(Cr)+ 3 / Cr0=-0.74V

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Q. Find $E_{cell}^\circ $ for the reaction :
$3Zn\left(\right.s\left.\right)+2\left(Cr\right)^{+ 3}\left(\right.aq.\left.\right) \rightarrow 3\left(Zn\right)^{+ 2}\left(\right.aq.\left.\right)+2Cr\left(\right.s\left.\right)$
Given : $E_{\left(\left(Zn\right)^{+ 2} / Zn\right)}^{o}=-0.76V;E_{\left(Cr\right)^{+ 3} / Cr}^{0}=-0.74V$

NTA AbhyasNTA Abhyas 2020

Solution:

$E_{cell}^{0}=E_{Cr^{3 +} / Cr}^{0}-E_{Zn^{2 +} / Zn}^{0}$