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Q. Find current in the branch $C D$ of the circuit.Physics Question Image

Current Electricity

Solution:

Circuit can be redrawn as
image
$R_{e q}=\frac{3}{2} \Omega ; I=\frac{V}{R_{e q}}=20 A$
Current in $C D, I_{C D}=I_{A C}+I_{B C} ; I_{C D}=15 A$