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Q.
Find all pairs of consecutive odd natural numbers, both of which are larger than $10$, such that their sum is less than $40$.
Linear Inequalities
Solution:
Let $x$ be the smaller of the two consecutive odd natural number, so that the other
one is $x+2$
Given $x>10$ and $x+(x+2)<40$
$\Rightarrow 2 x < 38$
$\Rightarrow x < 19$
$\therefore 10 < x < 19$
Since $x$ is an odd number, $x$ can take the values $11,13,15$ and 17 .
$\therefore $ Required possible pairs are $(11,13),(13,15),(15,17),(17,19)$