Question

Figure shows the volume versus temperature graph for the same mass of a gas (assumed ideal) corresponding to two different pressures $P_{1}$ and $P_{2}$. Then,

• A. $P_{1} > P_{2}$
• B. $P_{1} < P_{2}$
• C. $P_{1}=P_{2}$
• D. The information is insufficient

Answer 1

Answer: (A)

Since the graph is a straight line,
so, $V=mT$ where $m$ is the slope.
$=(n R T) / P$ [From equation of state]
or $m \propto(1 / P)$ or, $m_{2} > m_{1}$
$\therefore P_{2} < P_{1}$