Thank you for reporting, we will resolve it shortly
Q.
Figure shows the graph of acceleration of particle as a function of time. The maximum speed of the particle is (particle starts from rest)
Motion in a Straight Line
Solution:
Maximum speed will occur at $t = 4\,s,$ because till then a is positive. Now change in velocity is area under acceleration time graph, so
$v_{4s} - 0 = \frac{1}{2} [ 4\times 4] = 8$
$\Rightarrow v_{4s} = 8 \,m/s$
