Q.
Figure shows a wire of arbitrary shape of carrying $a$ current $i$ between points $a$ and $b$ . Let the length of the wire be $L$ and the distance between points $a$ and $b$ be $d$ . The wire lies in a plane at right angle to a uniform magnetic field $B$ . Then what is the force on the wire ?
NTA AbhyasNTA Abhyas 2020
Solution:
The force on a current carrying conductor in a uniform magnetic field is given by
$F=ilBSin\theta $
Here we have to consider only the effective length of the wire, which is equal to $d$ .
$l=d\theta =90^\circ \Rightarrow sin90^\circ =1$
So, the force on the wire will be equal to $idB$
$F=ilBSin\theta $
Here we have to consider only the effective length of the wire, which is equal to $d$ .
$l=d\theta =90^\circ \Rightarrow sin90^\circ =1$
So, the force on the wire will be equal to $idB$