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Q. Figure shows a man pulling a rope with such a force that the plank is held in position. The weights of the ropes, plank and pulleys are to be neglected. If $g=10 \,ms ^{-2}$ and the weight of the man is $80 \,kg\, f$, then the force with which the man pulls the rope is
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Laws of Motion

Solution:

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$T$ is tension due to ropes and $N$ is the normal force between mass and plank. The force with which man pulls down the rope is the Tension $T$ of the ro For equilibrium of man,
$T+N=m g$
$\Rightarrow T+3 T=m g$
$T=\frac{m g}{4}=\frac{80 \times 10}{4}=200 N$
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