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Q. Figure shows a circuit in which three identical diodes are used. Each diode has forward resistance of $20 \,\Omega$ and infinite backward resistance. Resistors $R_{1}=R_{2}=R_{3}=50\,\Omega$. Battery voltage is $6\, V$. The current through $R_3$ is:Physics Question Image

JEE MainJEE Main 2013Semiconductor Electronics: Materials Devices and Simple Circuits

Solution:

Here, diodes $D_1$ and $D_2$ are forward biased and $D_3$ is reverse biased.
Therefore current through $R_3$
$i=\frac{V}{R '}=\frac{6}{120}=\frac{1}{20}A=50\,mA$