Question

$FeCr_{2}O_{4}$ (chromite) is converted to $Cr$ by following steps:
Chromite $\xrightarrow{I} Na_{2} CrO_{4} \xrightarrow{II} Cr_{}O_{3} \xrightarrow{III} Cr, I,II$ and $III$ are

	$I$	$II$	$III$
1	$Na_{2}CO_{3} / air, \Delta$	$C$	$C$
2	$NaOH / air, \Delta$	$C,\Delta$	Al, $\Delta$
3	$NaOH/air, \Delta$	$C,\Delta$	Mg, $\Delta$
4	conc. $H_{2}SO_{4}, \Delta$	$NH_{4} Cl$	$C, \Delta$

• A. 1
• B. 2
• C. 3
• D. 4

Answer 1

Answer: (B)

$FeCr_{2}O_{4} \xrightarrow[\Delta]{NaOH/air} Na_{2}CrO_{4} \xrightarrow{C, \Delta} Cr_{2}O_{3} \xrightarrow{Al, \Delta}Cr$