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Q. $f : Z \rightarrow Z $ and $f(x) = x^2 $ then $f$ is

Relations and Functions - Part 2

Solution:

$f(-1) = f(1) = 1 \: \Rightarrow $ tis not one-one
$x^2 > 0 \, \forall x \in \: R \: \Rightarrow R$ ange of $\neq$ codomain