Question

$f(n) = \begin{cases} 0 &, \text{ x =0} \\[2ex] x-3, & \text{x > 0} \end{cases}$ The function $f (x)$ is

• A. increasing when $x \geq 0$
• B. strictly increasing when $x > 0$
• C. Strictly increasing at $x = 0$
• D. not continuous at $x = 0$ and so it is not increasing when $x > 0$

Answer 1

Answer: (B)

Given, $f(x)= \begin{cases}0, & , x=0 \\ x-3, & x > 0\end{cases}$

is clear from the graph that $f(x)$ is strictly increasing when $x>0$.