Question

$ {{F}_{g}} $ and $ {{F}_{g}} $ represent the gravitational and electric forces between the electrons at distance $10\, cm$, then the ratio of $ \frac{{{F}_{g}}}{{{F}_{e}}} $ will be

• A. $ {{10}^{42}} $
• B. 10
• C. 1
• D. $ {{10}^{-43}} $

Answer 1

Answer: (D)

$ \frac{{{F}_{g}}}{{{F}_{e}}}=\frac{G\frac{m.m}{{{r}^{2}}}}{\frac{1}{4\pi {{\varepsilon }_{0}}}.\frac{{{q}_{1}}{{q}_{2}}}{{{r}^{2}}}}=\frac{6.67\times {{10}^{-11}}\times (9.1\times {{10}^{-31}})}{9\times {{10}^{9}}\times {{(1.6\times {{10}^{-19}})}^{2}}} $ $ \approx {{10}^{-43}} $