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Q. $f :(0, \infty) \rightarrow\left(-\frac{\pi}{2}, \frac{\pi}{2}\right)$ be defined as, $f ( x )=\arctan (\ell nx )$
The above function can be classified as

Application of Derivatives

Solution:

$f(x)=\tan ^{-1}(\ln x)$
$\because \tan ^{-1}( x ) \& \ell n x$ are increasing functions.
$\Rightarrow f(x)$ is also increasing function.