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  4. Excess of NaOH (a q) was added to 100 m L of FeCl 3 (aq) resulting into 2.14 g of Fe ( OH )3. The molarity of FeCl 3( aq ) is: (Given molar mass of Fe =56 g mol -1 and molar mass of .Cl =35 ⋅ 5 g mol -1)

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Q. Excess of $NaOH _{(a q)}$ was added to $100\, m L$ of $FeCl _3$ (aq) resulting into $2.14\, g$ of $Fe ( OH )_3$. The molarity of $FeCl _3( aq )$ is : (Given molar mass of $Fe =56\, g \,mol { }^{-1}$ and molar mass of $\left.Cl =35 \cdot 5 \,g \,mol ^{-1}\right)$

JEE MainJEE Main 2017Some Basic Concepts of Chemistry

Solution:

$3 \,NaOH + FeCl _3 \rightarrow Fe ( CH )_3+ NaCl$
$100 \,ml \,\,2.14 \,gm$
$m =? $
Moles of $Fe \left( CH _3\right)=\frac{2.14}{107}=2 \times 10^{-2} \,mol$
moles $FeCl _3=2 \times 10^{-2} \,mol$
$M=\frac{2 \times 10^{-2}}{100} \times 1000=0.2\, M$