Question

$EtNH_2 + MeMgI \xrightarrow[\text{in the presence of pyridine}]{\text{Heated at high temp.}}$ GAS (A) The volume of gas (A) obtained at S.T.P. when $0.45\,gm$ of $EtNH _2$ reacts with $MeMgI$ is

• A. $224\, ml$
• B. $22.4\, ml$
• C. $448\, ml$
• D. $44.8 \, ml$

Answer 1

Answer: (C)

Only one hydrogen atom in $1^{\circ} RNH _2$ reactes at room temperature. In the presence of pyridine, both $H$ atoms in $1^{\circ} RNH _2$ react

One mole of $EtNH _2$ reacts with $2 \,mol$ of $MeMgI$ to give $2 \,mol$ of $CH _4$ (g). Molecular mass of $EtNH \,45\, gm$
Therefore, $45 \,gm$ of $EtNH _2$ gives $2 \times 22.4$ litres of $CH _4$ at S. T. P.
$0.45$ gm of EtNH ${ }_2$ gives $\frac{2 \times 22.4 \times 0.45}{45}=0.448$ litres $=448\, ml$