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  4. Ethyl methyl ketone on reduction with zinc amalgam and Conc. HCl gives:

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Q. Ethyl methyl ketone on reduction with zinc amalgam and Conc. HCl gives:

Aldehydes Ketones and Carboxylic Acids

Solution:

$C_2H_5 -\overset{\underset{||}{O}}{C} -CH_3 \xrightarrow[{\text{Conc.HCl}}]{{\text{Zn-Hg}} }C_{2}H_{5}CH_{2}CH_{3}$