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Q.
Ethyl acetate reacts with $NH_2NHCONH_2$ to form
KVPYKVPY 2013
Solution:
$NH_2NHCONH_2$ being more nucleophilic attack at the electrophilic carbonyl carbon of ethyl acetate group. Thus, ethyl acetate reacts with $NH_2NHCONH_2$ to form $CH_3CONHNHCONH_2$, which is a peptide linkage.
$CH_3\underset{\overset{||}{O}}{C}OC_2H_5 + H_2NNH\underset{\overset{||}{O}}{C}NH_2 \to CH_3 - \underset{\overset{||}{O}}{C}- NHNH\underset{\overset{||}{O}}{C} - NH_2$