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Q. Error in the measurement of radius of a sphere is $1\%$. Then maximum percentage error in the measurement of volume is

Physical World, Units and Measurements

Solution:

$V = \frac{4}{3}\pi r^{3}$;
$\frac{\Delta V}{V} \times100 = 3\left(\frac{\Delta r}{r}\right) \times100 =3 \times1\% = 3\%$