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  4. Equivalent weight of NH3 as a base is

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Q. Equivalent weight of $NH_{3}$ as a base is

Redox Reactions

Solution:

$\therefore NH_{3} +H^{+} \to NH_{4}^{+} $
As base, valence factor of $NH_{3 }is 1$
$\therefore Eq. wt. =17/1=17$